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9.8x^2-19x+5=0
a = 9.8; b = -19; c = +5;
Δ = b2-4ac
Δ = -192-4·9.8·5
Δ = 165
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{165}}{2*9.8}=\frac{19-\sqrt{165}}{19.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{165}}{2*9.8}=\frac{19+\sqrt{165}}{19.6} $
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